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NEW QUESTION: 1
Which three statements are true about Oracle Clusterware components, architecture, and behavior?
A. All cluster nodes can write or read from the Oracle Clusterware Repository (OCR) file at the same time.
B. The Cluster Ready Services Daemon (CRSD) is responsible for monitoring and maintaining the availability of cluster resources defined in the Oracle Local Repository file (OLR).
C. The Cluster Synchronization Services Daemon (CSSD) must connect to the cluster by accessing the Oracle Clusterware Repository (OCR) file before the Oracle High Availability Services Daemon (OHASD) is started.
D. Time synchronization in an Oracle Cluster is possible without using network Time Protocol (NTP).
E. The Oracle High Availability Services Daemon (OHASD) is responsible for monitoring and maintaining the availability of the Clusterware stack on a cluster node.
F. Voting disks stored in Automatic Storage Management (ASM) can be discovered or used even if the ASM instance on a cluster node is down.
Answer: D,E,F
Explanation:
Explanation/Reference:
Explanation:
F: To activate CTSS in your cluster, you must stop and deconfigure the vendor time synchronization service on all nodes in the cluster. CTSS detects when this happens and assumes time management for the cluster.
For example, to deconfigure NTP, you must remove or rename the ntp.conf file.
Incorrect Answers:
A: The CRS daemon (crsd) manages cluster resources based on the configuration information that is stored in OCR, not the OLR, for each resource.
B: You must update OCR through supported utilities such as Oracle Enterprise Manager, the Oracle Clusterware Control Utility (CRSCTL), the Server Control Utility (SRVCTL), the OCR configuration utility (OCRCONFIG), or the Database Configuration Assistant (DBCA) E: Please refer to the cluster startup picture below.
References: https://docs.oracle.com/cd/E11882_01/rac.112/e41959/intro.htm#CWADD90955
NEW QUESTION: 2
A Java application using thick JDBC connections will soon be deployed, and you must configure a RAC database to support highly available connections.
Broken connections must be re-established as quickly as possible.
Which feature will support this requirement?
A. Transparent Application Failover (TAF)
B. Fast Connection Failover (FCF) with Transparent Application Failover (TAF)
C. Transparent Application Failover (TAF) using Fast Application Notification (FAN)
D. Fast Connection Failover (FCF)
Answer: C
Explanation:
Explanation
The Fast Connection Failover (FCF) feature is an Oracle RAC/Fast Application Notification (FAN) client implemented through the connection pool. The feature requires the use of an Oracle JDBC driver and an Oracle RAC database.
https://docs.oracle.com/cd/B28359_01/java.111/e10788/rac.htm
NEW QUESTION: 3
You are designing a FabricPath network that connects to a spine-and-leaf topology using Layer 2 IS-IS as the IGP. The solution should be able to detect changes in the network topology and calculate loop-free paths to other nodes in the network that are being used as top-of-rack switches.
Which four options are characteristics of this FabricPath design solution? (Choose four.)
A. FabricPath Layer 2 IS-IS uses the standard IS-IS functionality to populate up to 16 routes for a given destination switch.
B. The FabricPath domain should be replaced because it does not run STP.
C. To use the basic FabricPathfunctionality, you must configure IS-IS on every interface between the leaf- and-spine switches.
D. The switch operating system uses multiple equal-cost, parallel links that provide ECMP.
E. Each switch computes its shortest path to every other switch in the network using the SPFalgorithm.
F. The interfaces in a FabricPath network run only the FabricPath Layer 2 IS-IS protocol with FTags disabled.
G. This path is used for forwarding unicast FabricPath frames.
Answer: A,D,E,G
Explanation:
Explanation/Reference:
Explanation:
The software sends hello packets on the FabricPath core ports to form adjacencies. After the software forms IS-IS adjacencies, the FabricPath unicast traffic uses the equal cost multipath(ECMP) feature of Layer 2 IS-IS to forward traffic. ECMP provides up to 16 paths for unicast traffic.
FabricPath Layer 2 IS-IS is based on the standard IS-IS protocol with the following extensions for the
FabricPath environment:
FabricPath has a single IS-ISarea with no hierarchical Layer 1/Layer 2 routing as prescribed within the
IS-IS standard. All switches within the FabricPath network are in a single Layer 1 area.
The switch uses a MAC address that is different from the MAC address used for Layer 3 IS-
ISinstances.
The software adds a new sub-TLV that carries switch ID information, which is not in standard IS-IS.
This feature allows Layer 2 information to be exchanged through the existing IS-IS protocol implementation.
Each switch computes its shortestpath to every other switch in the networkusing the shortest-path first
(SPF) algorithm. This path is used for forwarding unicast FabricPath frames. FabricPath Layer 2 IS-IS uses the standard IS-IS functionality to populate up to 16 routes for a given destination switch. The software uses multiple equal-cost available parallel links that provide ECMP.
FabricPath IS-IS introduces certain modifications to the standard IS-IS in order to support the
construction of broadcast and multicast trees (identified by the FTags). Specifically, using FabricPath, the software constructs two loop-free trees for forwarding multidestination traffic.
References:
NEW QUESTION: 4
展示を参照してください。
技術者が展示物の構成を図に示す2つの新しいルーターに貼り付けます。
それ以外の場合、ルータはデフォルト設定で設定されています。
ホスト1からホスト2へのpingは失敗しますが、技術者はホスト1からR2のS0 / 0インターフェイスへのpingを実行できます。
ホストの構成は正しいことが確認されました。問題の原因は何でしょうか。
A. R1のシリアルケーブルを交換する必要があります。
B. ip subnet-zeroコマンドを両方のルータで設定する必要があります。
C. R2のインターフェースが正しく設定されていません
D. R1には192.168.1.128ネットワークへの経路がありません。
E. IPアドレス指定方式に重複するサブネットワークがあります。
Answer: D
Explanation:
説明/参照：
Explanation:
ホスト2ネットワークを指すスタティックルートがないと、ルータはそのネットワークに到達するために必要なパスを認識できず、応答トラフィックを送信できません。