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NEW QUESTION: 1
회사는 게놈 정보를 수집하여 연구자들이 다양한 인구로부터 대량의 데이터 샘플을 수집 할 수 있도록 유전자 보고 장치를 개발하고 있습니다. 이 장치는 초당 8KB의 게놈 데이터를 데이터 플랫폼으로 푸시하여 데이터를 처리 및 분석하고 연구원에게 정보를 제공해야합니다. 데이터 플랫폼은 다음 요구 사항을 충족해야 합니다.
* 인바운드 게놈 데이터에 대한 거의 실시간 분석 제공
* 데이터가 유연하고 병렬 적이며 내구성이 있어야 합니다
* 데이터웨어 하우스에 처리 결과 제공
솔루션 아키텍트는 이러한 요구 사항을 충족시키기 위해 어떤 전략을 사용해야 합니까?
A. Amazon Kinesis Data Streams를 사용하여 인바운드 센서 데이터 수집, Kinesis 클라이언트로 데이터 분석 및 Amazon EMR을 사용하여 Amazon Redshift 더 스터에 결과 저장
B. Amazon Kinesis Data Firehose를 사용하여 인바운드 센서 데이터를 수집하고 Kinesis 클라이언트로 데이터를 분석한 후 결과를 Amazon RDS 인스턴스에 저장하십시오.
C. Amazon S3를 사용하여 인바운드 디바이스 데이터를 수집하고 Kinesis를 사용하여 Amazon SOS의 데이터를 분석한 후 결과를 Amazon Redshift 클러스터에 저장하십시오.
D. Amazon API Gateway를 사용하여 요청을 Amazon SQS 대기열에 넣고 AWS Lambda 함수로 데이터를 분석 한 다음 Amazon EMR을 사용하여 Amazon Redshift 클러스터에 결과를 저장합니다.
Answer: B
NEW QUESTION: 2
A computer was recently infected by malware after a flash drive was plugged in. The user, Ann, indicates she never opened any files or folders from the flash drive. A technician needs to prevent this from occurring in the future. Which of the following would accomplish this?
A. Set strong passwords
B. BitLocker To Go
C. Disable usermin
D. Disable AutoRun
Answer: D
NEW QUESTION: 3
Which line in the following OSPF configuration will not be required for MD5 authentication to work? interface GigabitEthernet0/1 ip address 192.168.10.1 255.255.255.0 ip ospf authentication message-digest
ip ospf message-digest-key 1 md5 CCNA
!
router ospf 65000
router-id 192.168.10.1
area 20 authentication message-digest
network 10.1.1.0 0.0.0.255 area 10
network 192.168.10.0 0.0.0.255 area 0
!
A. network 192.168.10.0 0.0.0.255 area 0
B. ip ospf message-digest-key 1 md5 CCNA
C. area 20 authentication message-digest
D. ip ospf authentication message-digest
Answer: C
NEW QUESTION: 4
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 8 kHz x 8-bit code words
C. 2 x 4 kHz x 8-bit code words
D. 2 x 4-bit code words x 8 kHz
Answer: C
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds
from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end
and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-
frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for
voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz
= 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice
about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second =
64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency
must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the
original perfectly from the sampled version."