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NEW QUESTION: 1
You and your colleague develop different parts of the same MAF application. He recently joined the company and needs to set up his workstation and devices for debugging. The application needs to be tested on Apple iPads and various Android-powered tablets. Your colleague has been assigned an Apple MacBook Pro as his workstation.
Which three tasks must you perform to ensure that your colleague will be able to debug the application on iOS and Android devices?
A. Register any Apple device involved in testing and debugging under the appropriate Apple Developer account.
B. Check that the settings in the Mobile Run configuration match those found in the cvm.properties file.
C. Make sure that the network device access option is enabled in the maf-application.xml file.
D. Disable USB debugging on all the Android devices involved because this will interfere the IDE's debugger.
E. Establish a Bluetooth link between your colleague's workstation and the devices.
F. Obtain a debug signing certificate from the Google Play store developer support.
Answer: A,B,C
Explanation:
Explanation/Reference:
References:

NEW QUESTION: 2
Which feature can be used to reduce the number of ICMP unreachable message egressing a router
A. Asymmetric routing
B. ICMP rate-limiting(upendra)
C. ip unreachables command
D. uRPF
Answer: B

NEW QUESTION: 3
View the exhibit and examine the structure of the EMPLOYEES table.

You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;
Answer: C

NEW QUESTION: 4

A. Option D
B. Option C
C. Option A
D. Option B
Answer: C