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NEW QUESTION: 1
Andrew works as a Forensic Investigator for PassGuide Inc. The company has a Windows-based environment. The company's employees use Microsoft Outlook Express as their e-mail client program. E- mails of some employees have been deleted due to a virus attack on the network.
Andrew is therefore assigned the task to recover the deleted mails. Which of the following tools can Andrew use to accomplish the task?
Each correct answer represents a complete solution. Choose two.
A. R-mail
B. eMailTrackerPro
C. EventCombMT
D. FINALeMAIL
Answer: A,D
NEW QUESTION: 2
Which two extensions does a fix pack have? (Choose two.)
A. jar
B. gzip
C. tar
D. pkg
E. iso
Answer: A,D
NEW QUESTION: 3
モバイルアプリケーションが共有を呼び出すために必要な秘密を格納するようにクラウドサービスを設定する必要があります。
あなたは解決策に何を含めるべきですか？ 答えるためには、答えの中で適切なオプションを選択してください、注：
それぞれ正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation
Every request made against a storage service must be authorized, unless the request is for a blob or container resource that has been made available for public or signed access. One option for authorizing a request is by using Shared Key.
Scenario: The mobile applications must be able to call the share pricing service of the existing retirement fund management system. Until the system is upgraded, the service will only support basic authentication over HTTPS.
The investment planning applications suite will include one multi-tier web application and two iOS mobile application. One mobile application will be used by employees; the other will be used by customers.
References: https://docs.microsoft.com/en-us/rest/api/storageservices/authorize-with-shared-key
NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2. Which Transact-SQL query should you use?
A. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
B. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode,Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: E
Explanation:
Explanation/Reference:
Explanation: