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NEW QUESTION: 1
솔루션 아키텍트는 대규모의 Windows 및 Linux 서버를위한 패치 계획을 수립해야 합니다.
패치 계획은 안전하게 구현되고 감사 준비가 되어야 하며 회사의 비즈니스 요구 사항을 준수해야 합니다.
최소 노력으로 이러한 요구 사항을 충족시키는 옵션은 무엇입니까?
A. 모든 인스턴스에서 AWS Systems Manager를 사용하여 패치를 관리하십시오. 프로덕션 외부에서 패치를 테스트 한 다음 적절한 승인을 받아 유지 관리 기간 동안 배포하십시오.
B. Chef Automate 용 AWS OpsWorks를 사용하여 지정된 유형의 모든 인스턴스를 반복하는 일련의 스크립트를 실행하십시오. 유지 보수 기간 동안 필요한 재시작을 포함하여 각 인스턴스에서 업데이트를 가져오고 설치하려면 적절한 OS 명령을 실행하십시오.
C. 모든 애플리케이션을 AWS OpsWorks로 마이그레이션하고 OpsWorks 자동 패치 지원을 사용하여 초기 설치 후 OS를 최신 상태로 유지하십시오. 감사 및 규정 준수보고를 제공하려면 AWS Config를 사용하십시오.
D. OS 네이티브 패치 서비스를 설치하고 사용하여 모든 인스턴스에 대한 업데이트주기 및 릴리스 승인을 관리하십시오. AWS Config를 사용하여 각 인스턴스의 OS 상태를 확인하고 패치 준수 문제를보고하십시오.
Answer: A

NEW QUESTION: 2
Before you install the Connector Server, what should you do? (Choose two)
A. Check that the Java Virtual Machine is already installed.
B. Check that the computer already contains either the Provisioning Server or the CA IdentityMinder Server.
C. Make sure that the time settings on all computers that will hold Connector Servers match.
D. Make sure that prerequisite packages are installed in the correct order on Red Hat 6.x systems.
Answer: C,D

NEW QUESTION: 3
You are creating a report in Power BI Desktop.
You are consuming the following tables.

Date[Date] is in the mm/dd/yyyy format. Date[DateKey] is in the ddmmyyyy format. Date[MonthNumber] is
in the mm format. Date[MonthName] is in the mmm format.
You create the report shown in the exhibit. (Click the Exhibit button.)

You need to ensure that the months appear in the order of the calendar.
How should you sort the MonthName column?
A. descending
B. ascending
C. by DateKey
D. by MonthNumber
Answer: D
Explanation:
Explanation/Reference:
References: http://ppmworks.com/sorting-month-names-chronologically-in-microsoft-power-bi-reports/

NEW QUESTION: 4
Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address?
A. 192.168.1.48/29
B. 192.168.1.40/29
C. 192.168.1.8/29
D. 192.168.1.32/27
E. 192.168.1.16/28
Answer: B
Explanation:
248 mask uses 5 bits (1111 1000)
42 IP in binary is (0010 1010)
The base subnet therefore is the lowest binary value that can be written without changing
the output of an AND operation of the subnet mask and IP...
1111 1000 AND
0010 1010 equals
0010 1000 - which is .40
/24 is standard class C mask.
Adding the 5 bits from the .248 mask gives /29