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NEW QUESTION: 1
A customer network engineer has made configuration changes that have resulted in some loss of connectivity.
You have been called in to evaluate a switch network and suggest resolutions to the problems.
PC2 in VLAN 200 is unable to ping the gateway address 172.16.200.1; identify the issue.
A. VLAN 200 not configured on SW2
B. VLAN 200 not configured on SW4
C. VLAN 200 not configured on SW1
D. VTP domain name mismatch on SW4
Answer: B
Explanation:
Explanation
By looking at the configuration for SW2, we see that it is missing VLAN 200, and the "switchport access vlan
200" command is missing under interface eth 0/0:
Topic 1, Ticket 1: Switch Port Trunk
Topology Overview (Actual Troubleshooting lab design is for below network design)
* Client Should have IP 10.2.1.3
* EIGRP 100 is running between switch DSW1 & DSW2
* OSPF (Process ID 1) is running between R1, R2, R3, R4
* Network of OSPF is redistributed in EIGRP
* BGP 65001 is configured on R1 with Webserver cloud AS 65002
* HSRP is running between DSW1
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution
Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-
* When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 Ipconfig ----- Client will be getting 169.X.X.X
* On ASW1 port Fa1/0/ 1 & Fa1/0/2 access port VLAN 10 was assigned which is using IP address
10.2.1.0/24
Sh run ------- & check for running config of int fa1/0/1 & fa1/0/2
interface FastEthernet1/0/1switchport mode accessswitchport access vlan 10interface FastEthernet1/0/2switchport mode accessswitchport access vlan 10
* We need to check on ASW 1 trunk port the trunk Po13 & Po23 were receiving VLAN 20 & 200 but not VLAN 10 so that switch could not get DHCP IP address and was failing to reach IP address of Internet
* Change required: On ASW1 below change is required for switch-to-switch connectivity..
int range portchannel13,portchannel23 switchport trunk allowed vlan none switchport trunk allowed vlan
10,200
NEW QUESTION: 2
When the procurement process is without a material master in SAP Materials Management, which configuration element do you assign to the valuation class?
Please choose the correct answer.
Response:
A. Valuation area
B. Item category
C. Material group
D. Material type
Answer: C
NEW QUESTION: 3
You are developing an application that includes a class named Warehouse. The Warehouse class includes a static property named Inventory- The Warehouse class is defined by the following code segment. (Line numbers are included for reference only.)
You have the following requirements:
* Initialize the _inventory field to an Inventory instance.
* Initialize the _inventory field only once.
* Ensure that the application code acquires a lock only when the _inventory object must be instantiated.
You need to meet the requirements.
Which three code segments should you insert in sequence at line 09? (To answer, move the appropriate code segments from the list of code segments to the answer area and arrange them in the correct order.)
Answer:
Explanation:
Explanation
After taking a lock you must check once again the _inventory field to be sure that other threads didn't instantiated it in the meantime.
First, you check if the inventory is null, if so, you lock it to avoid other threads to change it.
Second, you check again for the null, as in the tiny millisecond between check for null and locking could another thread get it.
Finally you create the instance and release the lock.
NEW QUESTION: 4
Sara, a security administrator, is noticing a slow down in the wireless network response. Sara launches a wireless sniffer and sees a large number of ARP packets being sent to the AP. Which of the following type of attacks is underway?
A. Packet sniffing
B. Interference
C. Blue jacking
D. IV attack
Answer: D
Explanation:
In this question, it's likely that someone it trying to crack the wireless network security.
An initialization vector is a random number used in combination with a secret key as a
means to encrypt data. This number is sometimes referred to as a nonce, or "number
occurring once," as an encryption program uses it only once per session.
An initialization vector is used to avoid repetition during the data encryption process,
making it impossible for hackers who use dictionary attack to decrypt the exchanged
encrypted message by discovering a pattern. This is known as an IV attack.
A particular binary sequence may be repeated more than once in a message, and the more
it appears, the more the encryption method is discoverable. For example if a one-letter
word exists in a message, it may be either "a" or "I" but it can't be "e" because the word "e"
is non-sensical in English, while "a" has a meaning and "I" has a meaning. Repeating the
words and letters makes it possible for software to apply a dictionary and discover the
binary sequence corresponding to each letter.
Using an initialization vector changes the binary sequence corresponding to each letter,
enabling the letter "a" to be represented by a particular sequence in the first instance, and
then represented by a completely different binary sequence in the second instance.
WEP (Wireless Equivalent Privacy) is vulnerable to an IV attack. Because RC4 is a stream
cipher, the same traffic key must never be used twice. The purpose of an IV, which is
transmitted as plain text, is to prevent any repetition, but a 24-bit IV is not long enough to
ensure this on a busy network. The way the IV was used also opened WEP to a related key
attack. For a 24-bit IV, there is a 50% probability the same IV will repeat after 5000
packets.