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NEW QUESTION: 1
あなたの会社はOracle Cloud Infrastructureでいくつかの小さなアプリケーションを実行しており、PeopleSoftをデプロイするための概念実証(POC)を計画しています。
既存のリソースがルートコンパートメントで維持されている場合、次のPOCのセキュリティを定義するための推奨アプローチは何ですか?
A. すべての新しいリソースをルートコンパートメントにプロビジョニングします。定義されたタグを使用して、異なるアプリケーションに属するリソースを分離します。
B. すべての新しいリソースをルートコンパートメントにプロビジョニングします。 POCに固有のリソースの作成と管理のみを許可する権限を付与します。
C. POCの新しいコンパートメントを作成し、コンパートメント内でリソースを作成および管理するための適切な権限を付与します。
D. POCの新しいテナントを作成します。すべての新しいリソースをルートコンパートメントにプロビジョニングします。ルートコンパートメント内でリソースを作成および管理するための適切な権限を付与します。
Answer: C
Explanation:
Explanation
If your organization is small, or if you are still in the proof-of-concept stage of evaluating OracleCloud Infrastructure, consider placing all of your resources in the root compartment (tenancy). This approach makes it easy for you to quickly view and manage all your resources. You can still write policies and create groups to restrict permissions on specific resources to only the users who need access.If you plan to maintain all your resources in the root compartment, we recommend setting up aseparate sandbox compartment to give users a dedicated space to try out features. In the sandbox compartment, you can grant users permissions to create and manage resources, whilemaintaining stricter permissions on the resources in your tenancy (root) compartment.
https://www.oracle.com/a/ocom/docs/best-practices-for-iam-on-oci.pdf

NEW QUESTION: 2
顧客材料情報レコードで何を識別できますか?この質問には3つの正解があります。
A. 特定のルートスケジュール
B. 特定の配送プラント
C. 顧客固有の価格
D. 特定の配送契約
E. 得意先品目コード
Answer: B,D,E

NEW QUESTION: 3
Sie arbeiten für ein Unternehmen, das mobile Anwendungen entwickelt. Sie unterhalten einen Server, auf dem die Spieleraufzeichnungen ihren verschiedenen Spielen zugewiesen werden. Das Trackingsystem ist neu und in Entwicklung.
Die Anwendung verwendet Entity Framework, um eine Verbindung zu einer Azure-Datenbank herzustellen. Die Datenbank enthält eine Spielertabelle und eine Spieltabelle.
Beim Hinzufügen eines Spielers sollte der Code einen neuen Spielerdatensatz einfügen und eine Beziehung zwischen einem vorhandenen Spielerdatensatz und dem neuen Spielerdatensatz hinzufügen.
Die Anwendung ruft CreatePlayerWithGame mit der richtigen gameId und der playerId auf, um den Vorgang zu starten.
(Zeilennummern dienen nur als Referenz.)

Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}